文 js和jquery中json对象合并的方法

如果需要将下面的json对象合并：

var a ={"a":"1","b":"2"}
var b ={"c":"3","d":"4","e":"5"}

想得到结果：

var c ={"a":"1","b":"2","c":"3","d":"4","e":"5"}

直接使用js的话，可以用一下方法：

<script>
function extend(des, src, override){
   if(src instanceof Array){
       for(var i = 0, len = src.length; i < len; i++)
            extend(des, src[i], override);
   }
   for( var i in src){
       if(override || !(i in des)){
           des[i] = src[i];
       }
   } 
   return des;
}
var a ={"a":"1","b":"2"}
var b ={"c":"3","d":"4","e":"5"}
var c = extend({}, [a,b]);
alert(c.a);
</script>

当然如果你加载了jquery,那就更方便了。可以使用$.extend()方法，该方法有两种模式;

jQuery.extend( target [, object1 ] [, objectN ] )  #将后面的对象合并到新的对象中{}

jQuery.extend( [deep ], target, object1 [, objectN ] )  #将后面的对象合并到新的对象中{},如果深度deep为true则将递归合并成为新对象.

实例：

<script type="text/javascript">
    # 请记得先加载jquery
    var a ={"a":"1","b":"2"}
    var b ={"c":"3","d":"4","e":"5"}
    var c = $.extend({}, a,b);
    console.log(c);
</script>